6a9d5736d6
This improves UX by using a alphanum sorting which is more natural to humans: [a1, a2, a10] instead of [a1, a10, a2]. Change-Id: Ice9c3de282f08e85c8f8a34a27d1b6c0502ca9cb Signed-off-by: Sorin Sbarnea <ssbarnea@redhat.com>
110 lines
2.9 KiB
Python
Executable File
110 lines
2.9 KiB
Python
Executable File
#!/usr/bin/env python
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# Copyright (C) 2012 OpenStack, LLC.
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#
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# Licensed under the Apache License, Version 2.0 (the "License");
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# you may not use this file except in compliance with the License.
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# You may obtain a copy of the License at
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#
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# http://www.apache.org/licenses/LICENSE-2.0
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#
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# Unless required by applicable law or agreed to in writing, software
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# distributed under the License is distributed on an "AS IS" BASIS, WITHOUT
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# WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. See the
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# License for the specific language governing permissions and limitations
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# under the License.
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"""
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Sorts using alphanum algorithm which can be explained as:
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Normal sort: ['a', 'a1', 'a10', 'a2']
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Alphanum sort: ['a', 'a1', 'a2', 'a10']
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It can sortof many kinds of objects, using name attribe if possible,
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otherwise it will try to use str().
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How to use:
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from alphanum import AlphanumSort
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sorted( foo, key=AlphanumSort)
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"""
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import re
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re_chunk = re.compile("([\D]+|[\d]+)")
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re_letters = re.compile("\D+")
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re_numbers = re.compile("\d+")
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def getchunk(item):
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itemchunk = re_chunk.match(item)
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# Subtract the matched portion from the original string
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# if there was a match, otherwise set it to ""
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item = (item[itemchunk.end():] if itemchunk else "")
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# Don't return the match object, just the text
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itemchunk = (itemchunk.group() if itemchunk else "")
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return (itemchunk, item)
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def cmp(a, b):
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return (a > b) - (a < b)
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def alphanum(a, b):
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a = a.name if hasattr(a, 'name') else str(a)
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b = b.name if hasattr(b, 'name') else str(b)
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n = 0
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while (n == 0):
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# Get a chunk and the original string with the chunk subtracted
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(ac, a) = getchunk(a)
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(bc, b) = getchunk(b)
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# Both items contain only letters
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if (re_letters.match(ac) and re_letters.match(bc)):
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n = cmp(ac, bc)
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else:
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# Both items contain only numbers
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if (re_numbers.match(ac) and re_numbers.match(bc)):
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n = cmp(int(ac), int(bc))
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# item has letters and one item has numbers, or one item is empty
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else:
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n = cmp(ac, bc)
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# Prevent deadlocks
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if (n == 0):
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n = 1
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return n
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class AlphanumSort(object):
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def __init__(self, obj, *args):
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self.obj = obj
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def __lt__(self, other):
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return alphanum(self.obj, other.obj) < 0
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def __gt__(self, other):
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return alphanum(self.obj, other.obj) > 0
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def __eq__(self, other):
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return alphanum(self.obj, other.obj) == 0
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def __le__(self, other):
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return alphanum(self.obj, other.obj) <= 0
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def __ge__(self, other):
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return alphanum(self.obj, other.obj) >= 0
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def __ne__(self, other):
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return alphanum(self.obj, other.obj) != 0
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if __name__ == "__main__":
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mylist = ['a2', 'a1', 'a10', 'a']
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assert sorted(mylist, key=AlphanumSort) == ['a', 'a1', 'a2', 'a10']
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