9aaddd5b48
In python 3 print statement is not supported, so we should use only print() functions. Fixes bug 1226943 Change-Id: If88d77982ddbd1eb47265f15a27b747cd8011e76
51 lines
1.5 KiB
Python
Executable File
51 lines
1.5 KiB
Python
Executable File
#!/usr/bin/env python
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# vim: tabstop=4 shiftwidth=4 softtabstop=4
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#
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# Licensed under the Apache License, Version 2.0 (the "License"); you may
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# not use this file except in compliance with the License. You may obtain
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# a copy of the License at
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#
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# http://www.apache.org/licenses/LICENSE-2.0
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#
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# Unless required by applicable law or agreed to in writing, software
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# distributed under the License is distributed on an "AS IS" BASIS, WITHOUT
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# WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. See the
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# License for the specific language governing permissions and limitations
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# under the License.
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import sys
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import os
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import yaml
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import json
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import re
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from heat.common import template_format
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def main():
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path = sys.argv[1]
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if os.path.isdir(path):
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convert_directory(path)
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elif os.path.isfile(path):
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convert_file(path)
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else:
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print('File or directory not valid: %s' % path)
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def convert_file(path):
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f = open(path, 'r')
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print(template_format.convert_json_to_yaml(f.read()))
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def convert_directory(dirpath):
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for path in os.listdir(dirpath):
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if not path.endswith('.template') and not path.endswith('.json'):
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continue
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yamlpath = re.sub('\..*$', '.yaml', path)
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print('Writing to %s' % yamlpath)
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f = open(os.path.join(dirpath, path), 'r')
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out = open(os.path.join(dirpath, yamlpath), 'w')
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yml = template_format.convert_json_to_yaml(f.read())
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out.write(yml)
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out.close()
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if __name__ == '__main__':
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main()
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