Files
deb-python-taskflow/taskflow/tests/unit/patterns/test_linear_flow.py
Joshua Harlow 2339bacaf7 Relax the linear flow symbol constraints
In order to make it possible to have a symbol
tree we need to relax and remove the constraints
that are being imposed by the linear constraints
and later move those constraint checks and validations
into the engines compilation stage.

Part of blueprint taskflow-improved-scoping

Change-Id: I6efdc821ff991e83572d89f56be5c678d007f9f8
2014-09-08 13:55:26 -07:00

121 lines
4.0 KiB
Python

# -*- coding: utf-8 -*-
# Copyright (C) 2014 Yahoo! Inc. All Rights Reserved.
#
# Licensed under the Apache License, Version 2.0 (the "License"); you may
# not use this file except in compliance with the License. You may obtain
# a copy of the License at
#
# http://www.apache.org/licenses/LICENSE-2.0
#
# Unless required by applicable law or agreed to in writing, software
# distributed under the License is distributed on an "AS IS" BASIS, WITHOUT
# WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. See the
# License for the specific language governing permissions and limitations
# under the License.
from taskflow.patterns import linear_flow as lf
from taskflow import retry
from taskflow import test
from taskflow.tests import utils
def _task(name, provides=None, requires=None):
return utils.ProvidesRequiresTask(name, provides, requires)
class LinearFlowTest(test.TestCase):
def test_linear_flow_starts_as_empty(self):
f = lf.Flow('test')
self.assertEqual(len(f), 0)
self.assertEqual(list(f), [])
self.assertEqual(list(f.iter_links()), [])
self.assertEqual(f.requires, set())
self.assertEqual(f.provides, set())
expected = 'taskflow.patterns.linear_flow.Flow: test; 0'
self.assertEqual(str(f), expected)
def test_linear_flow_add_nothing(self):
f = lf.Flow('test')
result = f.add()
self.assertIs(f, result)
self.assertEqual(len(f), 0)
def test_linear_flow_one_task(self):
f = lf.Flow('test')
task = _task(name='task1', requires=['a', 'b'], provides=['c', 'd'])
result = f.add(task)
self.assertIs(f, result)
self.assertEqual(len(f), 1)
self.assertEqual(list(f), [task])
self.assertEqual(list(f.iter_links()), [])
self.assertEqual(f.requires, set(['a', 'b']))
self.assertEqual(f.provides, set(['c', 'd']))
def test_linear_flow_two_independent_tasks(self):
task1 = _task(name='task1')
task2 = _task(name='task2')
f = lf.Flow('test').add(task1, task2)
self.assertEqual(len(f), 2)
self.assertEqual(list(f), [task1, task2])
self.assertEqual(list(f.iter_links()), [
(task1, task2, {'invariant': True})
])
def test_linear_flow_two_dependent_tasks(self):
task1 = _task(name='task1', provides=['a'])
task2 = _task(name='task2', requires=['a'])
f = lf.Flow('test').add(task1, task2)
self.assertEqual(len(f), 2)
self.assertEqual(list(f), [task1, task2])
self.assertEqual(list(f.iter_links()), [
(task1, task2, {'invariant': True})
])
self.assertEqual(f.requires, set())
self.assertEqual(f.provides, set(['a']))
def test_linear_flow_two_dependent_tasks_two_different_calls(self):
task1 = _task(name='task1', provides=['a'])
task2 = _task(name='task2', requires=['a'])
f = lf.Flow('test').add(task1).add(task2)
self.assertEqual(len(f), 2)
self.assertEqual(list(f), [task1, task2])
self.assertEqual(list(f.iter_links()), [
(task1, task2, {'invariant': True})
])
def test_linear_flow_three_tasks(self):
task1 = _task(name='task1')
task2 = _task(name='task2')
task3 = _task(name='task3')
f = lf.Flow('test').add(task1, task2, task3)
self.assertEqual(len(f), 3)
self.assertEqual(list(f), [task1, task2, task3])
self.assertEqual(list(f.iter_links()), [
(task1, task2, {'invariant': True}),
(task2, task3, {'invariant': True})
])
expected = 'taskflow.patterns.linear_flow.Flow: test; 3'
self.assertEqual(str(f), expected)
def test_linear_flow_with_retry(self):
ret = retry.AlwaysRevert(requires=['a'], provides=['b'])
f = lf.Flow('test', ret)
self.assertIs(f.retry, ret)
self.assertEqual(ret.name, 'test_retry')
self.assertEqual(f.requires, set(['a']))
self.assertEqual(f.provides, set(['b']))