# Copyright (c) 2013 Mirantis Inc. # # Licensed under the Apache License, Version 2.0 (the "License"); # you may not use this file except in compliance with the License. # You may obtain a copy of the License at # # http://www.apache.org/licenses/LICENSE-2.0 # # Unless required by applicable law or agreed to in writing, software # distributed under the License is distributed on an "AS IS" BASIS, # WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or # implied. # See the License for the specific language governing permissions and # limitations under the License. import os import pickle import sys from eventlet.green import subprocess from eventlet import timeout as e_timeout from oslo_log import log as logging from sahara import context from sahara import exceptions LOG = logging.getLogger(__name__) def _get_sub_executable(): return '%s/_sahara-subprocess' % os.path.dirname(sys.argv[0]) def start_subprocess(): return subprocess.Popen((sys.executable, _get_sub_executable()), close_fds=True, stdin=subprocess.PIPE, stdout=subprocess.PIPE, stderr=subprocess.PIPE) def run_in_subprocess(proc, func, args=(), kwargs={}, interactive=False): try: pickle.dump(func, proc.stdin) pickle.dump(args, proc.stdin) pickle.dump(kwargs, proc.stdin) proc.stdin.flush() if not interactive: result = pickle.load(proc.stdout) if 'exception' in result: raise exceptions.SubprocessException(result['exception']) return result['output'] finally: # NOTE(dmitryme): in openstack/common/processutils.py it # is suggested to sleep a little between calls to multiprocessing. # That should allow it make some necessary cleanup context.sleep(0) def _finish(cleanup_func): cleanup_func() sys.stdin.close() sys.stdout.close() sys.stderr.close() sys.exit(0) def shutdown_subprocess(proc, cleanup_func): try: with e_timeout.Timeout(5): # timeout would mean that our single-threaded subprocess # is hung on previous task which blocks _finish to complete run_in_subprocess(proc, _finish, (cleanup_func,)) except BaseException: # exception could be caused by either timeout, or # successful shutdown, ignoring anyway pass finally: kill_subprocess(proc) def kill_subprocess(proc): proc.stdin.close() proc.stdout.close() proc.stderr.close() try: proc.kill() except OSError: # could be caused by process already dead, so ignoring pass