57 lines
2.1 KiB
Python
57 lines
2.1 KiB
Python
#
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# Licensed under the Apache License, Version 2.0 (the "License"); you may
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# not use this file except in compliance with the License. You may obtain
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# a copy of the License at
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#
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# http://www.apache.org/licenses/LICENSE-2.0
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#
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# Unless required by applicable law or agreed to in writing, software
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# distributed under the License is distributed on an "AS IS" BASIS, WITHOUT
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# WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. See the
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# License for the specific language governing permissions and limitations
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# under the License.
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from heat.common import short_id
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from heat.engine import template
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def resource_templates(old_resources, resource_definition,
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num_resources, num_replace):
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"""
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Create the template for the nested stack of existing and new instances
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For rolling update, if launch configuration is different, the
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instance definition should come from the existing instance instead
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of using the new launch configuration.
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"""
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old_resources = old_resources[-num_resources:]
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num_create = num_resources - len(old_resources)
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num_replace -= num_create
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for i in range(num_resources):
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if i < len(old_resources):
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old_name, old_template = old_resources[i]
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if old_template != resource_definition and num_replace > 0:
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num_replace -= 1
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yield old_name, resource_definition
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else:
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yield old_name, old_template
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else:
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yield short_id.generate_id(), resource_definition
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def make_template(resource_definitions,
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version=('heat_template_version', '2013-05-23'),
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child_env=None):
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"""
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Return a Template object containing the given resource definitions.
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By default, the template will be in the HOT format. A different format
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can be specified by passing a (version_type, version_string) tuple matching
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any of the available template format plugins.
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"""
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tmpl = template.Template(dict([version]), env=child_env)
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for name, defn in resource_definitions:
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tmpl.add_resource(defn, name)
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return tmpl
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