9d98a0c24d
Unfortunately the only way we can know the user_id at this point is by parsing the error message. I also refactored the exceptions in openstack_auth to make them use different classes (but one common superclass). Partially implements blueprint: allow-users-change-expired-password Change-Id: Ieceee09db21040b96577db19bd195dc3799e3892
46 lines
1.5 KiB
Python
46 lines
1.5 KiB
Python
# Licensed under the Apache License, Version 2.0 (the "License");
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# you may not use this file except in compliance with the License.
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# You may obtain a copy of the License at
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#
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# http://www.apache.org/licenses/LICENSE-2.0
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#
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# Unless required by applicable law or agreed to in writing, software
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# distributed under the License is distributed on an "AS IS" BASIS,
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# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or
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# implied.
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# See the License for the specific language governing permissions and
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# limitations under the License.
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from django.conf.urls import url
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from django.views import generic
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from openstack_auth import utils
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from openstack_auth import views
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urlpatterns = [
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url(r"^login/$", views.login, name='login'),
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url(r"^logout/$", views.logout, name='logout'),
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url(r'^switch/(?P<tenant_id>[^/]+)/$', views.switch,
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name='switch_tenants'),
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url(r'^switch_services_region/(?P<region_name>[^/]+)/$',
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views.switch_region,
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name='switch_services_region'),
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url(r'^switch_keystone_provider/(?P<keystone_provider>[^/]+)/$',
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views.switch_keystone_provider,
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name='switch_keystone_provider'),
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]
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if utils.allow_expired_passowrd_change():
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urlpatterns.append(
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url(r'^password/(?P<user_id>[^/]+)/$', views.PasswordView.as_view(),
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name='password')
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)
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if utils.is_websso_enabled():
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urlpatterns += [
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url(r"^websso/$", views.websso, name='websso'),
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url(r"^error/$",
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generic.TemplateView.as_view(template_name="403.html"))
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]
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