Account for nodes with the same BMC hostname in inspection lookup
Currently, the code expects a given hostname to be used by one one node. This is not necessarily the case for Redfish where several Systems can co-exist under the same BMC. Use MAC addresses to distinguish them. Add more inline comments to explain the process. Change-Id: Ifc5a18bffc7cbcdd8bbbd660aba61fa11403e7e8
This commit is contained in:
parent
a42f23f475
commit
bf673c2761
@ -269,7 +269,17 @@ def lookup_node(context, mac_addresses, bmc_addresses, node_uuid=None):
|
||||
'state': node.provision_state})
|
||||
raise exception.NotFound()
|
||||
|
||||
# NOTE(dtantsur): in theory, if the node is found at this point, we could
|
||||
# short-circuit the lookup process and return it without considering BMC
|
||||
# addresses. However, I've seen cases where users ended up enrolling nodes
|
||||
# with BMC addresses from different nodes. Continuing to process BMC
|
||||
# addresses allows us to catch these situations that otherwise can lead
|
||||
# to updating wrong nodes.
|
||||
|
||||
if bmc_addresses:
|
||||
# NOTE(dtantsur): the same BMC hostname can be used by several nodes,
|
||||
# e.g. in case of Redfish. Find all suitable nodes first.
|
||||
nodes_by_bmc = set()
|
||||
for candidate in objects.Node.list(
|
||||
context,
|
||||
filters={'provision_state': states.INSPECTWAIT},
|
||||
@ -278,26 +288,41 @@ def lookup_node(context, mac_addresses, bmc_addresses, node_uuid=None):
|
||||
for addr in candidate.driver_internal_info.get(
|
||||
LOOKUP_CACHE_FIELD) or ():
|
||||
if addr in bmc_addresses:
|
||||
break
|
||||
else:
|
||||
continue
|
||||
nodes_by_bmc.add(candidate.uuid)
|
||||
|
||||
if node and candidate.uuid != node.uuid:
|
||||
# NOTE(dtantsur): if none of the nodes found by the BMC match the one
|
||||
# found by the MACs, something is definitely wrong.
|
||||
if node and nodes_by_bmc and node.uuid not in nodes_by_bmc:
|
||||
LOG.error('Conflict on inspection lookup: nodes %(node1)s '
|
||||
'and %(node2)s both satisfy MAC addresses '
|
||||
'(%(macs)s) and BMC address(s) (%(bmc)s). The cause '
|
||||
'may be ports attached to a wrong node.',
|
||||
{'node1': node.uuid,
|
||||
'node2': candidate.uuid,
|
||||
{'node1': ', '.join(nodes_by_bmc),
|
||||
'node2': node.uuid,
|
||||
'macs': ', '.join(mac_addresses),
|
||||
'bmc': ', '.join(bmc_addresses)})
|
||||
raise exception.NotFound()
|
||||
|
||||
# NOTE(dtantsur): at this point, if the node was found by the MAC
|
||||
# addresses, it also matches the BMC address. We only need to handle
|
||||
# the case when the node was not found by the MAC addresses.
|
||||
if not node and nodes_by_bmc:
|
||||
if len(nodes_by_bmc) > 1:
|
||||
LOG.error('Several nodes %(nodes)s satisfy BMC address(s) '
|
||||
'(%(bmc)s), but none of them satisfy MAC addresses '
|
||||
'(%(macs)s). Ports must be created for a successful '
|
||||
'inspection in this case.',
|
||||
{'nodes': ', '.join(nodes_by_bmc),
|
||||
'macs': ', '.join(mac_addresses),
|
||||
'bmc': ', '.join(bmc_addresses)})
|
||||
raise exception.NotFound()
|
||||
|
||||
node_uuid = nodes_by_bmc.pop()
|
||||
try:
|
||||
# Fetch the complete object now.
|
||||
node = objects.Node.get_by_uuid(context, candidate.uuid)
|
||||
node = objects.Node.get_by_uuid(context, node_uuid)
|
||||
except exception.NotFound:
|
||||
pass # Deleted in-between?
|
||||
raise # Deleted in-between?
|
||||
|
||||
if not node:
|
||||
LOG.error('No nodes satisfy MAC addresses (%(macs)s) and BMC '
|
||||
|
@ -381,6 +381,36 @@ class LookupNodeTestCase(db_base.DbTestCase):
|
||||
self.assertRaises(exception.NotFound, utils.lookup_node,
|
||||
self.context, self.macs, [self.bmc2], None)
|
||||
|
||||
def test_duplicate_bmc(self):
|
||||
# This can happen with Redfish. There is no way to resolve the conflict
|
||||
# other than by using MACs.
|
||||
obj_utils.create_test_node(
|
||||
self.context,
|
||||
uuid=uuidutils.generate_uuid(),
|
||||
driver_internal_info={utils.LOOKUP_CACHE_FIELD: [self.bmc]},
|
||||
provision_state=states.INSPECTWAIT)
|
||||
self.assertRaises(exception.NotFound, utils.lookup_node,
|
||||
self.context, [], [self.bmc], None)
|
||||
|
||||
def test_duplicate_bmc_and_unknown_mac(self):
|
||||
obj_utils.create_test_node(
|
||||
self.context,
|
||||
uuid=uuidutils.generate_uuid(),
|
||||
driver_internal_info={utils.LOOKUP_CACHE_FIELD: [self.bmc]},
|
||||
provision_state=states.INSPECTWAIT)
|
||||
self.assertRaises(exception.NotFound, utils.lookup_node,
|
||||
self.context, [self.unknown_mac], [self.bmc], None)
|
||||
|
||||
def test_duplicate_bmc_resolved_by_macs(self):
|
||||
obj_utils.create_test_node(
|
||||
self.context,
|
||||
uuid=uuidutils.generate_uuid(),
|
||||
driver_internal_info={utils.LOOKUP_CACHE_FIELD: [self.bmc]},
|
||||
provision_state=states.INSPECTWAIT)
|
||||
result = utils.lookup_node(
|
||||
self.context, [self.macs[0]], [self.bmc], None)
|
||||
self.assertEqual(self.node.uuid, result.uuid)
|
||||
|
||||
def test_by_uuid(self):
|
||||
result = utils.lookup_node(self.context, [], [], self.node.uuid)
|
||||
self.assertEqual(self.node.uuid, result.uuid)
|
||||
|
@ -0,0 +1,6 @@
|
||||
---
|
||||
fixes:
|
||||
- |
|
||||
Fixes the inspection lookup to consider all nodes with the same BMC
|
||||
hostname, as can happen with Redfish. In this case, the nodes are
|
||||
distinguished by MAC addresses.
|
Loading…
Reference in New Issue
Block a user