Fix service_type normalization

The previous version of the function would fail poorly when service_type
is None. Put in an if to fix it.

Change-Id: Ibbeee913afc463705fe781c2ef0918deb1303617
Story: 2003314
This commit is contained in:
Monty Taylor 2018-08-06 10:34:06 -05:00
parent 2441006a71
commit e11dc0f670
No known key found for this signature in database
GPG Key ID: 7BAE94BC7141A594
2 changed files with 34 additions and 1 deletions

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@ -24,7 +24,8 @@ SERVICE_TYPES_URL = "https://service-types.openstack.org/service-types.json"
def _normalize_type(service_type):
return service_type.replace('_', '-')
if service_type:
return service_type.replace('_', '-')
class ServiceTypes(object):

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@ -0,0 +1,32 @@
# -*- coding: utf-8 -*-
# Licensed under the Apache License, Version 2.0 (the "License"); you may
# not use this file except in compliance with the License. You may obtain
# a copy of the License at
#
# http://www.apache.org/licenses/LICENSE-2.0
#
# Unless required by applicable law or agreed to in writing, software
# distributed under the License is distributed on an "AS IS" BASIS, WITHOUT
# WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. See the
# License for the specific language governing permissions and limitations
# under the License.
"""
test_misc
---------
Miscellaneous tests
"""
from os_service_types import service_types
from os_service_types.tests import base
class TestMisc(base.TestCase):
def test_normalize(self):
self.assertEqual('foo-bar', service_types._normalize_type('foo_bar'))
def test_normalize_none(self):
self.assertIsNone(service_types._normalize_type(None))