Update untils_find_resource to support no unique matches error

Utils_find_resource function cannot raise a no-unique-match error
when manager (eg. image) has no find() function.
It just deletes the first match.

Change-Id: I0caa9d3985ce5c01ef418f62d3ee5677886e0240

osc_lib/tests/test_utils.py

@@ -431,6 +431,36 @@ class TestFindResource(test_utils.TestCase):
         self.manager.get.assert_called_with(self.name)
         self.manager.find.assert_called_with(name=self.name)
 
+    def test_find_resource_silly_resource_no_unique_match(self):
+        # We need a resource with no resource_class for this test, start fresh
+        self.manager = mock.Mock()
+        self.manager.get = mock.Mock(side_effect=Exception('Boom!'))
+        self.manager.find = mock.Mock(
+            side_effect=AttributeError(
+                "'Controller' object has no attribute 'find'",
+            )
+        )
+        silly_resource = FakeOddballResource(
+            None,
+            {'id': '12345', 'name': self.name},
+            loaded=True,
+        )
+        silly_resource_same = FakeOddballResource(
+            None,
+            {'id': 'abcde', 'name': self.name},
+            loaded=True,
+        )
+        self.manager.list = mock.Mock(return_value=[silly_resource,
+                                                    silly_resource_same])
+        result = self.assertRaises(exceptions.CommandError,
+                                   utils.find_resource,
+                                   self.manager,
+                                   self.name)
+        self.assertEqual("More than one resource exists "
+                         "with the name or ID 'legos'.", str(result))
+        self.manager.get.assert_called_with(self.name)
+        self.manager.find.assert_called_with(name=self.name)
+
     def test_format_dict(self):
         expected = "a='b', c='d', e='f'"
         self.assertEqual(expected,

osc_lib/utils.py

@@ -151,15 +151,23 @@ def find_resource(manager, name_or_id, **kwargs):
         else:
             pass
 
+    # for client with no find function
+    count = 0
     for resource in manager.list():
-        # short circuit and return the first match
         if (resource.get('id') == name_or_id or
                 resource.get('name') == name_or_id):
-            return resource
-    else:
+            count += 1
+            _resource = resource
+    if count == 0:
         # we found no match, report back this error:
         msg = _("Could not find resource %s")
         raise exceptions.CommandError(msg % name_or_id)
+    elif count == 1:
+        return _resource
+    else:
+        # we found multiple matches, report back this error
+        msg = _("More than one resource exists with the name or ID '%s'.")
+        raise exceptions.CommandError(msg % name_or_id)
 
 
 def format_dict(data):