openstack
/
project-config
Code Issues Proposed changes

Fix failure detection in irc access check 

Two problems are corrected:

1) If a channel is not registered with chanserv, consider it an
access failure.

2) The failure flag was being reset on every successful private
message.  That was intended to ensure that we failed if we were
unable to communicate with ChanServ.  But the logic was flawed.
Correct this by treating the failure flag as trinary.  On the
first channel where we have verified access is okay, set the flag
to indicate that we have not failed, iff the flag has not already
been set.  So now either failure to communicate with ChanServ or
an actual access failure will cause it to exit 1.

Change-Id: I8d51b706ed6f499827f8046ab4522b342589cb90
This commit is contained in:
James E. Blair 2015-03-18 09:59:29 -07:00 committed by Andreas Jaeger
parent 8ae55a6364
commit d1673c9063
1 changed files with 14 additions and 3 deletions
Show Stats Download Patch File Download Diff File Expand all files Collapse all files

17
tools/check_irc_access.py
View File

@ -40,10 +40,10 @@ class CheckAccess(irc.client.SimpleIRCClient):
self.flags = flags
self.current_channel = None
self.current_list = []
self.failed = True
self.failed = None
def on_disconnect(self, connection, event):
if self.failed:
if self.failed is not False:
sys.exit(1)
else:
sys.exit(0)
@ -73,7 +73,6 @@ class CheckAccess(irc.client.SimpleIRCClient):
self.log.debug("Ignoring message from unauthenticated "
"user %s" % nick)
return
self.failed = False
self.advance(msg)
def advance(self, msg=None):
@ -87,6 +86,13 @@ class CheckAccess(irc.client.SimpleIRCClient):
self.current_channel)
time.sleep(1)
return
if msg.endswith('is not registered.'):
self.failed = True
print ("%s is not registered with ChanServ." %
self.current_channel)
self.current_channel = None
self.advance()
return
if msg.startswith('End of'):
found = False
for nick, flags, msg in self.current_list:
@ -102,6 +108,11 @@ class CheckAccess(irc.client.SimpleIRCClient):
for nick, flags, msg in self.current_list:
print msg
print
# If this is the first channel checked, set the failure
# flag to false because we know that the system is
# operating well enough to check at least one channel.
if self.failed is None:
self.failed = False
self.current_channel = None
self.advance()
return