ec6abb3dbe
In Python 3 __ne__ by default delegates to __eq__ and inverts the result, but in Python 2 they urge you to define __ne__ when you define __eq__ for it to work properly [1].There are no implied relationships among the comparison operators. The truth of x==y does not imply that x!=y is false. Accordingly, when defining __eq__(), one should also define __ne__() so that the operators will behave as expected. [1]https://docs.python.org/2/reference/datamodel.html#object.__ne__ Change-Id: I50234892bd3dadcda533d97c03414067e06ef0f4 Closes-Bug: #1586268
38 lines
1.5 KiB
Python
38 lines
1.5 KiB
Python
# Licensed under the Apache License, Version 2.0 (the "License"); you may
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# not use this file except in compliance with the License. You may obtain
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# a copy of the License at
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#
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# http://www.apache.org/licenses/LICENSE-2.0
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#
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# Unless required by applicable law or agreed to in writing, software
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# distributed under the License is distributed on an "AS IS" BASIS, WITHOUT
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# WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. See the
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# License for the specific language governing permissions and limitations
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# under the License.
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from congressclient.openstack.common.apiclient import base as common_base
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from congressclient.tests import utils
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class BaseTest(utils.TestCase):
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def test_resource_repr(self):
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r = common_base.Resource(None, dict(foo="bar", baz="spam"))
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self.assertEqual(repr(r), "<Resource baz=spam, foo=bar>")
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def test_eq(self):
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# Two resources of the same type with the same id: equal
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r1 = common_base.Resource(None, {'id': 1, 'name': 'hi'})
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r2 = common_base.Resource(None, {'id': 1, 'name': 'hello'})
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self.assertEqual(r1, r2)
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# Two resources with no ID: equal if their info is equal
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r1 = common_base.Resource(None, {'name': 'joe', 'age': 12})
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r2 = common_base.Resource(None, {'name': 'joe', 'age': 12})
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self.assertEqual(r1, r2)
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# Two resources of different types: never equal
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r1 = common_base.Resource(None, {'id': 1})
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self.assertNotEqual(r1, object())
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self.assertNotEqual(r1, {'id': 1})
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