python-manilaclient/manilaclient/v1/services.py
Valeriy Ponomaryov 1cc313e5cf Use Resource class from common code
Replace own implementation of 'Resource' class with
same one from common apiclient code.

Partially implements: blueprint use-common-code

Change-Id: I87ac06931a23721fc8cc2d58b5a9473618073f32
2014-08-04 05:26:28 -04:00

51 lines
1.6 KiB
Python

# Copyright 2014 OpenStack LLC.
# All Rights Reserved.
#
# Licensed under the Apache License, Version 2.0 (the "License"); you may
# not use this file except in compliance with the License. You may obtain
# a copy of the License at
#
# http://www.apache.org/licenses/LICENSE-2.0
#
# Unless required by applicable law or agreed to in writing, software
# distributed under the License is distributed on an "AS IS" BASIS, WITHOUT
# WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. See the
# License for the specific language governing permissions and limitations
# under the License.
import six
try:
from urllib import urlencode # noqa
except ImportError:
from urllib.parse import urlencode # noqa
from manilaclient import base
from manilaclient.openstack.common.apiclient import base as common_base
RESOURCES_PATH = '/os-services'
RESOURCES_NAME = 'services'
class Service(common_base.Resource):
def __repr__(self):
return "<Service: %s>" % self.id
class ServiceManager(base.Manager):
"""Manage :class:`Service` resources."""
resource_class = Service
def list(self, search_opts=None):
"""Get a list of all services.
:rtype: list of :class:`Service`
"""
query_string = ''
if search_opts:
query_string = urlencode(
sorted([(k, v) for (k, v) in six.iteritems(search_opts) if v]))
if query_string:
query_string = "?%s" % query_string
return self._list(RESOURCES_PATH + query_string, RESOURCES_NAME)