Fix 'keypair show' command output
The attempt to get the data dict out of the keypair resource object uses a key 'keypair. This is incorrect, no key is required. Closes-Bug: 1289594 Change-Id: I7887119c1d800d389cb6f63ea7847bea1e25bb52
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@ -146,7 +146,7 @@ class ShowKeypair(show.ShowOne):
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parsed_args.name)
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parsed_args.name)
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info = {}
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info = {}
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info.update(keypair._info['keypair'])
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info.update(keypair._info)
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if not parsed_args.public_key:
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if not parsed_args.public_key:
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del info['public_key']
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del info['public_key']
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return zip(*sorted(six.iteritems(info)))
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return zip(*sorted(six.iteritems(info)))
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