74 lines
2.6 KiB
Python
74 lines
2.6 KiB
Python
# Licensed under the Apache License, Version 2.0 (the "License"); you may
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# not use this file except in compliance with the License. You may obtain
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# a copy of the License at
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#
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# http://www.apache.org/licenses/LICENSE-2.0
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#
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# Unless required by applicable law or agreed to in writing, software
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# distributed under the License is distributed on an "AS IS" BASIS, WITHOUT
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# WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. See the
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# License for the specific language governing permissions and limitations
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# under the License.
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#
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"""Image v1 API Library"""
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from openstackclient.api import api
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class APIv1(api.BaseAPI):
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"""Image v1 API"""
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_endpoint_suffix = '/v1'
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def __init__(self, endpoint=None, **kwargs):
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super(APIv1, self).__init__(endpoint=endpoint, **kwargs)
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self.endpoint = self.endpoint.rstrip('/')
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self._munge_url()
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def _munge_url(self):
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# Hack this until discovery is up
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if not self.endpoint.endswith(self._endpoint_suffix):
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self.endpoint = self.endpoint + self._endpoint_suffix
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def image_list(
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self,
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detailed=False,
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public=False,
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private=False,
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**filter
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):
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"""Get available images
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:param detailed:
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Retrieve detailed response from server if True
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:param public:
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Return public images if True
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:param private:
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Return private images if True
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If public and private are both True or both False then all images are
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returned. Both arguments False is equivalent to no filter and all
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images are returned. Both arguments True is a filter that includes
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both public and private images which is the same set as all images.
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http://docs.openstack.org/api/openstack-image-service/1.1/content/requesting-a-list-of-public-vm-images.html
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http://docs.openstack.org/api/openstack-image-service/1.1/content/requesting-detailed-metadata-on-public-vm-images.html
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http://docs.openstack.org/api/openstack-image-service/1.1/content/filtering-images-returned-via-get-images-and-get-imagesdetail.html
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"""
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url = "/images"
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if detailed or public or private:
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# Because we can't all use /details
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url += "/detail"
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image_list = self.list(url, **filter)['images']
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if public != private:
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# One is True and one is False, so public represents the filter
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# state in either case
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image_list = [i for i in image_list if i['is_public'] == public]
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return image_list
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