python-openstackclient/openstackclient/compute
Huanxuan Ao 681d6dc2de Make "flavor show" command to show a private flavor properly
The "flavor show" command could not show a
private flavor by flavor name becauce it could
not find a private flavor by flavor name.
In "until.find_resource(parsed_args.flavor)",
If parsed_args.falvor is a name of a flavor,
"flavors.find(name=parsed_args.flavor)"will be
called to find a flavor.But the default value of
"is_public" is "Ture" in "flavors.find()" so that
we can only find public flavors.If we want to find
all flaovrs by flavor name,we should add
"is_public=None" in "flavors.find()".

So I tried to change
"until.find_resource(parsed_args.flavor)" to
"until.find_resource(parsed_args.flavor, is_public=None)",
but then I could not find any flavor by flavor id
because "is_public" is an unexpected argument of
"flavors.get()" in "until.find_resource()".

In this case,I think "until.find_resource()"
can not find a private flavor properly,and
we should combine "manager.get(flavor.id)" and
"manager.find(name=flavor.name, is_public=None)"
by ourselve to find a flavor.

Also,this bug affects other flavor commands like
"flavor set/unset/delete",so I fix them in this patch too.

Change-Id: I4a4ed7b0a2f522ee04d1c3270afcda7064285c39
Closes-Bug: #1575478
2016-05-02 16:47:53 +08:00
..
v2 Make "flavor show" command to show a private flavor properly 2016-05-02 16:47:53 +08:00
__init__.py Remove copyright from empty files 2014-01-20 17:28:13 +04:00
client.py Replace string format arguments with function parameters 2016-02-20 14:16:25 +08:00