tempest/tempest/common/utils/data_utils.py
David Kranz 88d4f7c19a Reduce chance of name collision for resources.
I am not sure how to make this totally reliable without using long uuids but this should reduce
the chance of collision from one in thousands to one in millions, more than enough to make this not be the weakest link
of build failure. It can be improved in the future if necessary.

Change-Id: I0337db0e1bf7a028855a3d18b8eb9894e1a436bf
2013-03-27 11:16:37 -04:00

78 lines
2.0 KiB
Python

# vim: tabstop=4 shiftwidth=4 softtabstop=4
# Copyright 2012 OpenStack, LLC
# All Rights Reserved.
#
# Licensed under the Apache License, Version 2.0 (the "License"); you may
# not use this file except in compliance with the License. You may obtain
# a copy of the License at
#
# http://www.apache.org/licenses/LICENSE-2.0
#
# Unless required by applicable law or agreed to in writing, software
# distributed under the License is distributed on an "AS IS" BASIS, WITHOUT
# WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. See the
# License for the specific language governing permissions and limitations
# under the License.
import itertools
import random
import re
import urllib
from tempest import exceptions
def rand_name(name='test'):
return name + str(random.randint(1, 0x7fffffff))
def rand_int_id(start=0, end=0x7fffffff):
return random.randint(start, end)
def build_url(host, port, api_version=None, path=None,
params=None, use_ssl=False):
"""Build the request URL from given host, port, path and parameters."""
pattern = 'v\d\.\d'
if re.match(pattern, path):
message = 'Version should not be included in path.'
raise exceptions.InvalidConfiguration(message=message)
if use_ssl:
url = "https://" + host
else:
url = "http://" + host
if port is not None:
url += ":" + port
url += "/"
if api_version is not None:
url += api_version + "/"
if path is not None:
url += path
if params is not None:
url += "?"
url += urllib.urlencode(params)
return url
def parse_image_id(image_ref):
"""Return the image id from a given image ref."""
return image_ref.rsplit('/')[-1]
def arbitrary_string(size=4, base_text=None):
"""
Return size characters from base_text, repeating the base_text infinitely
if needed.
"""
if not base_text:
base_text = 'test'
return ''.join(itertools.islice(itertools.cycle(base_text), size))