API: Don't debug output when exception reaches wsgi layer
Unless of course we ask for it Change-Id: Iab51e854bca3b21b83133dd44ebc6bdd8641e2fd
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@@ -224,6 +224,6 @@ def main():
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keyfile=args.ssl_keyfile,
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server_side=True
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)
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wsgi.server(ssl_sock, api, keepalive=False)
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wsgi.server(ssl_sock, api, keepalive=False, debug=args.debug)
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return 0
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