71 lines
2.5 KiB
Python
71 lines
2.5 KiB
Python
# Copyright 2015 VMware, Inc. All rights reserved.
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#
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# Licensed under the Apache License, Version 2.0 (the "License"); you may
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# not use this file except in compliance with the License. You may obtain
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# a copy of the License at
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#
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# http://www.apache.org/licenses/LICENSE-2.0
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#
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# Unless required by applicable law or agreed to in writing, software
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# distributed under the License is distributed on an "AS IS" BASIS, WITHOUT
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# WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. See the
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# License for the specific language governing permissions and limitations
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# under the License.
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import logging
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import sys
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from neutron.i18n import _LI
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LOG = logging.getLogger(__name__)
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def output_header(func):
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"""Decorator to demarcate the output of various hooks.
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Based on the callback function name we add a header to the
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cli output. Callback name's should follow the convention of
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component_operation_it_does to leverage the decorator
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"""
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def func_desc(*args, **kwargs):
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component = '[%s]' % func.func_name.split('_')[0].upper()
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op_desc = [n.capitalize() for n in func.func_name.split('_')[1:]]
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LOG.info(_LI('==== %(component)s %(operation)s ===='),
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{'component': component, 'operation': ' '.join(op_desc)})
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return func(*args, **kwargs)
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func_desc.__name__ = func.func_name
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return func_desc
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def query_yes_no(question, default="yes"):
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"""Ask a yes/no question via raw_input() and return their answer.
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"question" is a string that is presented to the user.
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"default" is the presumed answer if the user just hits <Enter>.
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It must be "yes" (the default), "no" or None (meaning
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an answer is required of the user).
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The "answer" return value is True for "yes" or False for "no".
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"""
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valid = {"yes": True, "y": True, "ye": True,
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"no": False, "n": False}
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if default is None:
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prompt = " [y/n] "
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elif default == "yes":
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prompt = " [Y/n] "
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elif default == "no":
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prompt = " [y/N] "
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else:
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raise ValueError("invalid default answer: '%s'" % default)
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while True:
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sys.stdout.write(question + prompt)
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choice = raw_input().lower()
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if default is not None and choice == '':
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return valid[default]
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elif choice in valid:
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return valid[choice]
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else:
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sys.stdout.write("Please respond with 'yes' or 'no' "
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"(or 'y' or 'n').\n")
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