ee3339c8e6
I've managed to get better at grepping for this and this finds some of the stragglers. They are all file opens without closes fixed by using a with open() context manager. Change-Id: I7b8c8516a86558e2027cb0f01aefe2dd1849069c
71 lines
1.9 KiB
Python
Executable File
71 lines
1.9 KiB
Python
Executable File
#!/usr/bin/env python
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# Licensed under the Apache License, Version 2.0 (the "License"); you may
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# not use this file except in compliance with the License. You may obtain
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# a copy of the License at
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#
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# http://www.apache.org/licenses/LICENSE-2.0
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#
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# Unless required by applicable law or agreed to in writing, software
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# distributed under the License is distributed on an "AS IS" BASIS, WITHOUT
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# WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. See the
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# License for the specific language governing permissions and limitations
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# under the License.
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import os
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from zuul.lib import yamlutil as yaml
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FIXTURE_DIR = os.path.join(os.path.dirname(__file__),
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'fixtures')
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CONFIG_DIR = os.path.join(FIXTURE_DIR, 'config')
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def make_playbook(path):
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d = os.path.dirname(path)
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try:
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os.makedirs(d)
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except OSError:
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pass
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with open(path, 'w') as f:
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f.write('- hosts: all\n')
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f.write(' tasks: []\n')
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def handle_repo(path):
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print('Repo: %s' % path)
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config_path = None
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for fn in ['zuul.yaml', '.zuul.yaml']:
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if os.path.exists(os.path.join(path, fn)):
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config_path = os.path.join(path, fn)
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break
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try:
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with open(config_path) as f:
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config = yaml.safe_load(f)
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except Exception:
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print(" Has yaml errors")
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return
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for block in config:
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if 'job' not in block:
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continue
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job = block['job']['name']
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playbook = os.path.join(path, 'playbooks', job + '.yaml')
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if not os.path.exists(playbook):
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print(' Creating: %s' % job)
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make_playbook(playbook)
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def main():
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repo_dirs = []
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for root, dirs, files in os.walk(CONFIG_DIR):
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if 'zuul.yaml' in files or '.zuul.yaml' in files:
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repo_dirs.append(root)
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for path in repo_dirs:
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handle_repo(path)
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if __name__ == '__main__':
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main()
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