062dcc9cb2
To reproduce:
>>> from keystoneauth1 import exceptions
>>> e = exceptions.ClientException(message="test")
>>> print(e.message)
None
Change-Id: If73df85768866fb93d90ff95479f29f64aabe73f
Co-Authored-By: Gage Hugo <gagehugo@gmail.com>
Closes-Bug: #1534363
33 lines
1.2 KiB
Python
33 lines
1.2 KiB
Python
# Licensed under the Apache License, Version 2.0 (the "License"); you may
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# not use this file except in compliance with the License. You may obtain
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# a copy of the License at
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#
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# http://www.apache.org/licenses/LICENSE-2.0
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#
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# Unless required by applicable law or agreed to in writing, software
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# distributed under the License is distributed on an "AS IS" BASIS, WITHOUT
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# WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. See the
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# License for the specific language governing permissions and limitations
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# under the License.
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from keystoneauth1 import exceptions
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from keystoneauth1.tests.unit import utils
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class ExceptionTests(utils.TestCase):
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def test_clientexception_with_message(self):
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test_message = 'Unittest exception message.'
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exc = exceptions.ClientException(message=test_message)
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self.assertEqual(test_message, exc.message)
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def test_clientexception_with_no_message(self):
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exc = exceptions.ClientException()
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self.assertEqual(exceptions.ClientException.__name__,
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exc.message)
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def test_using_default_message(self):
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exc = exceptions.AuthorizationFailure()
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self.assertEqual(exceptions.AuthorizationFailure.message,
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exc.message)
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