Using assertIsNone() instead of assertEqual(None)
TrivilalFix Following OpenStack Style Guidelines: [1] http://docs.openstack.org/developer/hacking/#unit-tests-and-assertraises [H203] Unit test assertions tend to give better messages for more specific assertions. As a result, assertIsNone(...) is preferred over assertEqual(None, ...) and assertIs(..., None) Change-Id: Ifcac62f400ec15017a1db06ba889ed5e2d6a07f0
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@@ -498,13 +498,13 @@ class TestFindResource(test_utils.TestCase):
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utils.format_dict({'a': 'b', 'c': 'd', 'e': 'f'}))
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self.assertEqual(expected,
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utils.format_dict({'e': 'f', 'c': 'd', 'a': 'b'}))
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self.assertEqual(None, utils.format_dict(None))
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self.assertIsNone(utils.format_dict(None))
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def test_format_list(self):
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expected = 'a, b, c'
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self.assertEqual(expected, utils.format_list(['a', 'b', 'c']))
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self.assertEqual(expected, utils.format_list(['c', 'b', 'a']))
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self.assertEqual(None, utils.format_list(None))
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self.assertIsNone(utils.format_list(None))
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def test_format_list_of_dicts(self):
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expected = "a='b', c='d'\ne='f'"
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@@ -514,7 +514,7 @@ class TestFindResource(test_utils.TestCase):
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self.assertEqual(expected, utils.format_list_of_dicts(unsorted_data))
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self.assertEqual('', utils.format_list_of_dicts([]))
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self.assertEqual('', utils.format_list_of_dicts([{}]))
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self.assertEqual(None, utils.format_list_of_dicts(None))
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self.assertIsNone(utils.format_list_of_dicts(None))
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def test_format_list_separator(self):
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expected = 'a\nb\nc'
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