Quote URL in curl output to handle query params
Copy and pasting the generated curl output into a shell doesn't work when the URL includes an ampersand, as the URL isn't quoted. Closes-Bug: #1249891 Change-Id: Ic3d7682a2c034e89c3367c858ea33510f8cbc7d4
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@@ -95,7 +95,7 @@ def request(url, method='GET', headers=None, original_ip=None, debug=False,
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if method:
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string_parts.append(' -X %s' % method)
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string_parts.append(' %s' % url)
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string_parts.append(" '%s'" % url)
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if headers:
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for header in six.iteritems(headers):
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