openstack/releases
Code Issues Proposed changes

show the governance tags for a deliverable in list-changes

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Sometimes evaluating the changes requires knowing how the deliverables
are set up in the governance repository. For example, releases from
"stable" branches of projects that do not claim to follow the stable
release process can be evaluated more leniently.

Change-Id: I9337d5ab77bcfc302af65f755a801f8b20f839f9
Signed-off-by: Doug Hellmann <doug@doughellmann.com>
This commit is contained in:
Doug Hellmann
2016-07-13 12:59:47 -04:00
parent 6b43c704c3
commit 98168291d5
1 changed files with 28 additions and 0 deletions
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28
openstack_releases/cmds/list_changes.py
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@@ -30,6 +30,7 @@ import yaml
from openstack_releases import defaults
from openstack_releases import gitutils
from openstack_releases import governance
def header(title):
@@ -113,6 +114,8 @@ def main():
print('not cleaning up %s' % workdir)
atexit.register(cleanup_workdir)
team_data = governance.get_team_data()
# Remove any inherited PAGER environment variable to avoid
# blocking the output waiting for input.
os.environ['PAGER'] = ''
@@ -126,6 +129,31 @@ def main():
with open(filename, 'r') as f:
deliverable_info = yaml.load(f.read())
header('team info')
if 'team' in deliverable_info:
team_name = deliverable_info['team']
team_dict = team_data.get(team_name)
if team_dict:
team = governance.Team(team_name, team_dict)
print('found team %s' % team_name)
deliverable_name = os.path.basename(filename)[:-5] # remove .yaml
deliverable = team.deliverables.get(deliverable_name)
if deliverable:
print('found deliverable %s' % deliverable_name)
for rn, repo in sorted(deliverable.repositories.items()):
print('\nrepo %s\ntags:' % repo.name)
for t in repo.tags:
print(' %s' % t)
else:
print(('no deliverable %r found for team %r, '
'cannot report on governance status') %
(deliverable_name, team_name))
else:
print('no team %r found, cannot report on governance status' %
team_name)
else:
print('no team name given, cannot report on governance status')
series = os.path.basename(
os.path.dirname(
os.path.abspath(filename)