wsme/doc/integrate.rst
2011-10-22 16:48:15 +02:00

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Integrating with a Framework
============================
WSGI Application
----------------
:mod:`wsme.wsgi` -- WSGI adapter
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
.. module:: wsme.wsgi
.. function:: adapt
Returns a wsgi application that serve a :class:`wsme.controller.WSRoot`.
Example
~~~~~~~
.. code-block:: python
from wsme import *
import wsme.wsgi
class MyRoot(WSRoot):
@expose(unicode)
def helloworld(self):
return u"Hello World !"
application = wsme.wsgi.adapt(
MyRoot(protocols=['restjson']))
Pyramid
-------
The WSRoot._handle_request method is a valid pyramid view:
.. code-block:: python
from paste.httpserver import serve
from pyramid.config import Configurator
from wsme import *
class WSController(WSRoot):
@expose(int)
@validate(int, int)
def multiply(self, a, b):
return a * b
myroot = WSRoot()
myroot.addprotocol('restjson')
myroot.addprotocol('extdirect')
if __name__ == '__main__':
config = Configurator()
config.add_route('ws', '')
config.add_view(wsroot._handle_request, route_name='ws')
app = config.make_wsgi_app()
serve(app, host='0.0.0.0')
Turbogears 1.x
--------------
:mod:`wsme.tg1` -- TG1 adapter
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
.. module:: wsme.tg1
.. class:: Controller(wsroot)
A TG1 Controller that publish a :class:`wsme.WSRoot`.
.. function:: adapt
Returns a :class:`Controller` that publish a :class:`wsme.WSRoot`.
Example
~~~~~~~
In a freshly quickstarted tg1 application (let's say, wsmedemo),
the prefered way is the following :
Create a new file, "wsmedemo/ws.py" :
.. code-block:: python
import wsme.tg1
from wsme import expose, validate, WSRoot
class WSController(WSRoot):
@expose(int)
@validate(int, int)
def multiply(self, a, b):
return a * b
Insert the ws controller in the controller tree, (file controllers.py):
.. code-block:: python
# ...
from wsmedemo.ws import WSController
import wsme.tg1
class Root(controllers.RootController):
ws = wsme.tg1.adapt(
WSController(webpath='/ws', protocols=['restjson']))
# ...